C. False typo in alpha() The first line of code creates a list with one element, which is ‘alpha;beta;gamma’. However, the delimiter used in the split method is ‘:’ instead of ‘;’, so the list will only contain one element. The second line of code joins all elements in the list into a single string, which will be ‘alpha;beta;gamma’. The third line of code checks if the string ‘alpha;beta;gamma’ contains only alphabetic characters, which is False because it contains ‘;’.

there is a typo, is ; instead of : so its B "true"

Only if there is a typo in 'isaplpha()' and it means actually 'isalpha()' the it's C

Another question with a possible typo. Is it supposed to be 'isalpha()' or 'isaplpha()'? Using 'isalpha()' gives a False and using 'isaplpha()' gives an error

Answer C; #Example_1 the_list='alpha;beta;gamma'.split(":") print(the_list) the_string=''.join(the_list) print(the_string) print(the_string.isalpha()) # Output: # ['alpha;beta;gamma'] # alpha;beta;gamma # False #Example_2 the_list='alpha:beta:gamma'.split(":") print(the_list) the_string=''.join(the_list) print(the_string) print(the_string.isalpha()) # Output: # ['alpha', 'beta', 'gamma'] # alphabetagamma # True

C- False: the_list='alpha;beta;gamma'.split(":") >>> the_list ['alpha;beta;gamma'] >>> the_string=''.join(the_list) >>> the_string 'alpha;beta;gamma' >>> print(the_string.isalpha()) False

It outputs: False. Because of .split(":") output of the_list is list with one element ["alpha;beta;gamma"]

I agree with roncr, the ; should be : instead. Also isaplpha() should be isalpha(). Once those are corrected it returns True

Hi, check the code twice before give your answers. If you read correctly the code if you execute it you will see that as it's wrote the response is an exception, so the answer is A. Normally, you need to answer as you have in the questionnaire

C. it outputs False