PCAP Exam - Question 90

Question

What is the expected behavior of the following code?

Examice · Accepted Answer

The code provided is intended to show the use of Python's string manipulation methods. First, it uses the 'split' method on the string 'alpha;beta;gamma' with ':' as the delimiter, which results in a list containing one element: ['alpha;beta;gamma']. Then, it joins this list back into a single string 'alpha;beta;gamma' using the empty string '' as the join character. Finally, it checks if this string ('alpha;beta;gamma') is composed solely of alphabetic characters using the 'isalpha' method. Since the string contains the ';' character, which is not alphabetic, the 'isalpha' method will return False. Therefore, the expected behavior of the code is to print 'False'.

aferiver · Answer

C. False

typo in alpha()

The first line of code creates a list with one element, which is ‘alpha;beta;gamma’. However, the delimiter used in the split method is ‘:’ instead of ‘;’, so the list will only contain one element.

The second line of code joins all elements in the list into a single string, which will be ‘alpha;beta;gamma’.

The third line of code checks if the string ‘alpha;beta;gamma’ contains only alphabetic characters, which is False because it contains ‘;’.

lukaki · Answer

Answer C;

#Example_1
the_list='alpha;beta;gamma'.split(":")
print(the_list)
the_string=''.join(the_list)
print(the_string)
print(the_string.isalpha())

# Output:
# ['alpha;beta;gamma']
# alpha;beta;gamma
# False

#Example_2
the_list='alpha:beta:gamma'.split(":")
print(the_list)
the_string=''.join(the_list)
print(the_string)
print(the_string.isalpha())

# Output:
# ['alpha', 'beta', 'gamma']
# alphabetagamma
# True

sadako11 · Answer

Another question with a possible typo. Is it supposed to be  'isalpha()'  or 'isaplpha()'?
Using 'isalpha()' gives a False  and using 'isaplpha()' gives an error

carpmatias · Answer

Only if there is a typo in 'isaplpha()' and it means actually 'isalpha()' the it's C

roncr · Answer

there is a typo, is ; instead of : so its B "true"

mazimir · Answer

It outputs: False.

Because of .split(":") output of the_list is list with one element ["alpha;beta;gamma"]

Efren · Answer

C- False:

the_list='alpha;beta;gamma'.split(":")
	   
>>> the_list
	   
['alpha;beta;gamma']

>>> the_string=''.join(the_list)
	   
>>> the_string
	   
'alpha;beta;gamma'
>>> print(the_string.isalpha())
	   
False

macxsz · Answer

C. it outputs False

mplopez · Answer

Hi, check the code twice before give your answers. If you read correctly the code if you execute it you will see that as it's wrote the response is an exception, so the answer is A.
Normally, you need to answer as you have in the questionnaire

Bonesaw · Answer

I agree with roncr, the ; should be : instead. Also isaplpha() should be isalpha(). Once those are corrected it returns True

Dave304409 · Answer

is correct

PCAP Exam - Question 90

Discussion