PCEP-30-02 Exam - Question 13

let's analyze what's happening in the given code: str1 = 'Peter' assigns the string 'Peter' to the variable str1. str2 = str1[:] creates a slice of str1 that includes all characters (from beginning to end). This effectively creates a copy of the string. In Python, strings are immutable, which means when you create a copy of a string using slicing, it creates a new string object with the same content. Therefore, the correct answer is: A. str1 and str2 are different (but equal) strings. This is true because: str1 and str2 contain the same characters ('Peter') They are equal in terms of content However, they are separate string objects in memory Options B, C, and D are incorrect: B is wrong because they are not the same string object, but two different objects with the same content. C and D are incorrect because both strings have the same length.

B is the answer

The correct answer is A, since str2 get all the elements from str1, but it's a new variable, new string. If you change str1, str2 remains unchanged

str1 = 'Peter' str2 = str1 print(id(str1), id(str2)) #same memory location : 123262391172144, 123262391172144 str2 = 'hell' print(str1, str2) print(id(str1), id(str2)) #on manipulation memory changes : 123262391172144, 123262391705072 hence, Str1 & Str2 are same Strings but different name.

A is correct. Slicing creates a copy of the string. Therefore, they are different strings, but if you compare them for equality you the result will be True as they have the same content.

The answer is B. For sure. Since strings are immutable and they have the same contents they both refer to the same memory location.

b is the correct answer

B is the correct answer, because their memory addresses are same if you check in your IDE. hence B. str1 and str2 are different names of the same strings.

Since there is a slicing the str2 made a copy of str1.

str = "Peter" str2 = str[:] print(id(str)) print(id(str2)) the ID is identical , so B