PCEP-30-02 Exam - Question 3

Question

What is the expected output of the following code?

Examice · Accepted Answer

Vihaan_C · Answer

x=[0,1,2]
x=[1,0,1,2]
x=[1,1,2]
sum=1+1+2=4

consultsk · Answer

The given code performs the following operations:

1. `x = [0, 1, 2]`: Initializes the list `x` with the elements `[0, 1, 2]`.
2. `x.insert(0, 1)`: Inserts the value `1` at index `0`, so the list becomes `[1, 0, 1, 2]`.
3. `del x[1]`: Deletes the element at index `1`, so the list becomes `[1, 1, 2]`.
4. `print(sum(x))`: Calculates the sum of the elements in the list `x` and prints it.

Now, the list `x` is `[1, 1, 2]`, and the sum of these elements is `1 + 1 + 2 = 4`.

**Expected output:** `4`

hovnival · Answer

let's break down the code step by step to understand the result:
Code:

x = [0, 1, 2]  # Step 1: x is initialized as [0, 1, 2].
x.insert(0, 1) # Step 2: Inserts 1 at index 0. x becomes [1, 0, 1, 2].
del x[1]       # Step 3: Deletes the element at index 1. x becomes [1, 1, 2].
print(sum(x))  # Step 4: Calculates the sum of elements in x, which is 1 + 1 + 2 = 4.

Result:

The output of the code is 4.

christostz03 · Answer

b is the correct answer

megan_mai · Answer

x.insert(0,1) >> insert value 1 to x[0] >> The new x = [1,0,1,2]
del x[1] >> delete x[1] >> delete value 0 in x
sum(x) = 1+1+2 = 4

Chandiz · Answer

list.insert(index, value)

Manisshaa · Answer

x = [0,1,2]
x.insert(0,1) #which means insertion in list at zero index.Hence, x = [1,0,1,2]
del x[1] # At index 1 in list the element is 0 .Hence x become [1,1,2]
print(sum(x) # sum all elements in list [1,1,2] is 4
Hence, Option B is the correct one.

PCEP-30-02 Exam - Question 3

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