Section Two Quantitative

Here you have the best Test Prep GRE Section 2 Quantitative practice exam questions

  • You have 49 total questions to study from
  • Each page has 5 questions, making a total of 10 pages
  • You can navigate through the pages using the buttons at the bottom
  • This questions were last updated on November 21, 2024
Question 1 of 49

    Correct Answer: B

    B

    You can make the comparison quickly by recognizing that Quantity A is the

    "difference of two squares" (

    ) in the factored form (x + y) (x -y), where y= 2. Or, you can multiply the two binomials in Column A, and then simplify:

    Quantity A

Question 2 of 49

    Correct Answer: D

    D

    The centered information establishes that Quantity B, pq, must be negative, because the product of a positive number and a negative number is always negative.

    As for Quantity A, try substituting some simple numbers for p and q. If p= 1 and q= -1, then p+q= 0 while pq= -1, and therefore

    Thus, which quantity is greater depends on the values of p and q.

Question 3 of 49

    Correct Answer: D

    The relationship between x - y and q - p cannot be determined from the information given because we don't have sufficient information about the specific values or relationships of x, y, p, and q. Without knowing the exact measurements or the context of these variables, it is impossible to ascertain whether one quantity is greater than, less than, or equal to the other. Any assumptions about their relative sizes would be speculative.

Question 4 of 49

    Correct Answer: A

    A

    Any fraction between 0 and 1 is greater than the square of that fraction. Thus,a +b must be greater than

Question 5 of 49

A rectangular ribbon of paper is looped to form a circular ring having a diameter that measures twice the rings height.

    Correct Answer: C

    C

    The rings height is equal to its radius. To determine Quantity A (the surface area of

    the outside of the ring), multiply the rings circumference by its height (r): SA =

    .

    To determine Quantity B (twice the rings circular area), multiply 2 by the bases area:

    . As you can see, the two quantities are equal.