An administrator arrives at work and begins their morning checks on a four node, all-flash vSAN Cluster. They notice the vSAN datastore reached 99% capacity due to a single node failure.
How can the administrator provide temporary relief?
An administrator arrives at work and begins their morning checks on a four node, all-flash vSAN Cluster. They notice the vSAN datastore reached 99% capacity due to a single node failure.
How can the administrator provide temporary relief?
To provide temporary relief when the vSAN datastore reaches 99% capacity due to a single node failure, the administrator should change FTT=1 with RAID-1 (Mirroring) to FTT=0 No data redundancy. This reduces the space used by mirror copies, immediately freeing up storage space and reducing the datastore capacity usage. However, it is important to note that this approach removes data redundancy and can cause data loss if another failure occurs. Therefore, it should be used only as a temporary measure while resolving the primary issue.
I think C as this will free up the capacity used by the mirror copies of the components. B is incorrect as you will require a min of 4 hosts for Raid 5. Changing from Raid 1 to Raid 5 will require additional space during the rebuild process.
But there are 4-nodes - or?: "...begins their morning checks on a four node, all-flash vSAN Cluster."
Yeap, there are four nodes and one of them crashed, so still we have 3 nodes and RAID5 will only be able to exist on 3 nodes with Force Provisioning ( but there is nothing about it in any of the answers)
I would go with C, since no compliance was violated hence tells me it is Mirror FTT1 existing and loss of one host only impacted capacity and not compliance , how ever C is NOT supported by VMware but doable Important: Use of a VM storage policy with FTT = 0 (No Data Redundancy) is not supported and can cause data loss if there is a failure or if the VM becomes unresponsive. https://docs.vmware.com/en/VMware-Cloud-on-AWS/services/com.vmware.vsphere.vmc-aws-manage-data-center-vms.doc/GUID-EDBB551B-51B0-421B-9C44-6ECB66ED660B.html
I think C as this will free up the capacity used by the mirror copies of the components.
C. Since it did not say it was now out of compliance (RAID 5 requires a min of 4 hosts) and now there are only 3. Plus RAID 1 FTT1 only requires 3 and Rec 4 so it would still be in compliance and takes up 2X the space, thus the 99% capacity.