A00-212 Exam - Question 12

The program calculates the average years of employment for names that are unique to WORK.ONE, i.e., names in WORK.ONE that do not appear in WORK.TWO. The names in WORK.ONE are Joyce, John, Jane, and Tomas, and their corresponding years of employment are 9, 4, 6, and 8. The names in WORK.TWO are Joyce, John, Robert, Bob, and Jeff. Therefore, the names unique to WORK.ONE are Jane and Tomas, with years of employment 6 and 8 respectively. The average of these values is (6 + 8) / 2 = 7.