For you who thought it was AD, here is the explanation: When you have an array in a variable and set it to another variable, they share the same id, that means they point to the same array. a = [1] b = a print(id(a), id(b)) # same id Since a==b, when you set a[0] = 0, you are "also" doing b[0] = 0

A and C are correct. a = [1] b = a a[0] = 0 print(len(a) == len(b)) # True print(a[0] == b[0]) # True

a and b are the same list A. len(a) == len (b) C. a [0] == b [0]

The Answer is suprisingly A & C, i thought it was A & D until i tried it

A & C is correct.

Correct Answer is A C

A & D Are the correct answers.

a=[1] b=a a[0]=0 print(len(a)==len(b))#True print(b[0]+1 == a[0])#False print(a[0] == b[0])#True print(a[0]+1 == b[0])#False Ans is A,C

After executing the snippet: a = a[0] = 0 b = b[0] = 1

A and C are correct

if you print(b[0]) it will print 0, so the answer is A and C.

a=[1] b=a a[0]=0 print(len(a) == len(b)) -> True print(a[0] == b[0]) --> True print(b[0] + 1 == a[0]) --> False print(a[0] + 1 == b[0]) --> False My answer is A and C

Correct answer is A C

A C are correct