PCAP Exam - Question 80

Question

What is the expected behavior of the following code?

Examice · Accepted Answer

C.

stuartz · Answer

A if ':' after except ArithmeticError else SyntaxError.  1/0 will raise ZeroDivision error which will be caught by the ArithmeticError at both levels with a m sum of 3.

aferiver · Answer

B, the question is incorrect.

m = 0

def foo(n):
    global m
    assert m != 0

try:
        return 1/n  # 1/0 is ZeroDivisionError
    except ArithmeticError:
        raise ValueError

try:
    foo(0)
except ArithmeticError:
    m += 2
except:
    m += 1  # Because is ZeroDivisionError, 0+1= 1

print(m)  # Print 1

it_man_531 · Answer

"C" is correct answer.
colon is missing in    except ArithmeticError     hence it will return a SyntaxError

vlobachevsky · Answer

A is correct

DTL001 · Answer

Answer is C

The real exam has :
except ArithmeticError:

m = 0

def foo(n):
    global m
    assert m != 0
    try:
        return 1/n
    except ArithmeticError:
        raise ValueError

try:
    foo(0)
except ArithmeticError:
    m +=2
except:
    m +=1
print(m)  # Print  1

codedatakage · Answer

I have implemented the code, and I get the answer "A". I write here the code to help to test it.

m = 0
def foo(n):
    global m
    assert m==0
    try:
        return 1/n
    except ArithmeticError:
        m+=1
        raise

try:
    foo(0)
except ArithmeticError:
    m+=2
except:
    m+=1
print(m)# print: 3

Jnanada · Answer

If it wasnt for Type Error, Answer is A.

ahuja · Answer

Answer is A: 1, it throws AssertionError, hence goes to m+=1

Mallie · Answer

A.
Two arithmetic errors. The 'raise' in the example doesn't specify an error so it continues handling a 'ZeroDivisionError'. (This all assumes the second colon is put in of course)

swatiphadtare · Answer

If code doesnt have type then answer is D

m = 0
def foo(n):
    global m
    assert m == 0
    try:
        return 1/n
    except ArithmeticError:
        m=m+1
        raise ValueError
try:
    foo(0)
except ArithmeticError:
    m +=2
except:
    m +=1
print(m) # Prints 2

emanuelcar990 · Answer

the awnser its C SyntaxError: 'return' outside function
and its 1 /n  and the its global m = 0 and not  n

Ujjal_d · Answer

Which is correct?

zantrz · Answer

The answer is A.
m = 0
def foo(n):
    global m
    assert m == 0 #raises an AssertionError if m is equal to 0. This is a check to ensure that m is zero.
    try:
        return 1/n
    except ArithmeticError: #there is ZeroDivisionError so m will be 0+1 = 1
        m+=1
        raise #if we add "raise" we get the exception error

try: #the outer try block calls the foo(0) function, which will raise an ArithmeticError (precisily ZeroDivisionError)
    foo(0)
except ArithmeticError:  #this block will be executed
        m +=2 # so we add 1 +2 = 3
except:
        m +=1  #If any other exception occurs, m is incremented by 1, and the current value of m is printed. In case of foo(0) this block will not be executed.

print(m) # Prints 3

PCAP Exam - Question 80

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