Which of the following snippets will execute without raising any unhandled exceptions? (Choose two.)
A.

B.

C.

D.
Which of the following snippets will execute without raising any unhandled exceptions? (Choose two.)
A.
B.
C.
D.
AC
Correct Answer: AC.
Correct Answer AC B - ValueError will be thrown.
What is wrong with answer B? Looks like correct option as well
You're right, that snippet prints 0 and doesn't raise any exception.
In B,else block will be executed and it will throw "ValueError: invalid literal for int() with base 10: ''"
i think answer BC !!
B: ----> 6 print(int("")) ValueError: invalid literal for int() with base 10: '' C:----> 6 print(float("1c1")) ValueError: could not convert string to float: '1c1'
Answer: BC
sorry, answer is A and C
try: print(0/0) except: print(0/1) else: print(0/2) #try: # print(int("0")) #except NameError: # print("0") #else: # print(int(""))#ValueError: invalid literal for int() with base 10: '' import math try: print(math.sqrt(-1)) except: print(math.sqrt(0)) else: print(math.sqrt(1)) #try: # print(float("1e1")) #except (NameError, SystemError): # print(float("1a1")) #else: # print(float("1c1"))#ValueError: could not convert string to float: '1c1' Ans is A,C