Exam PCAP-31-03 All QuestionsBrowse all questions from this exam
Question 9

What is the expected behavior of the following code?

    Correct Answer: A

    The code initializes the variable m to 0. The function foo is defined to take an argument n. Inside foo, it is asserted that m is 0. The function then tries to return the result of 1 divided by n. When foo(0) is called, a ZeroDivisionError occurs as division by zero is not allowed. The catch block for ArithmeticError increments m by 1 and re-raises the exception. The outer try-except block catches the ArithmeticError, increments m by 2, and does not re-raise the exception. A generic exception block is present but will not be executed. Therefore, m is incremented first by 1 in the inner except block and then by 2 in the outer except block, resulting in m being 3 at the end of the execution. Hence, the output of the code is 3.

Discussion
FasterN8Option: A

Tested, A is correct. The raise keyword here does not raise a generic exception. "When we do not give any exception class name with the raise keyword, it reraises the exception that last occurred." So that line in the function re-raises the ArithmeticError a second time.

Dave304409Option: A

is correct

DKAT2023Option: A

A is correct