Python's built in function named open () tries to open a file and returns:
Python's built in function named open () tries to open a file and returns:
The open() function in Python is used to open a file and it returns a file object. This file object can be used to read, write, and modify the file. It serves as a stream object that connects the program with the file on disk, allowing for file operations to be performed.
answer is C :a stream object str1=open('C:/Users/avinayan/PycharmProjects/Alexa_poc/db/user_list_1.txt','rt') print(str1) Output: <_io.TextIOWrapper name='C:/Users/avinayan/PycharmProjects/Alexa_poc/db/user_list_1.txt' mode='rt' encoding='cp1252'>
don't know the answer is A, C is correct answer
Agree. CORRECT answer is C.
The answer is 'C. a stream object'
The open() function returns a file object which can used to read, write and modify the file.
C should be the correct answer
C should be the correct one
file= open() print (file) TypeError: open() missing required argument 'file' B
wrong, you are using the function not declaring at least a file name, correct answer is C
The open() function returns a file object which can used to read, write and modify the file.
C. a stream object