PCAP Exam - Question 87

Question

What is the expected behavior of the following code?

Examice · Accepted Answer

A.

Efren · Answer

If im not wrong, is B)
string=str(1/3) ---- this is equal a 0.3333333333

dummy=''
	  
>>> for character in string:
	  dummy=character+dummy

>>> dummy
	  
'3333333333333333.0'

print(dummy[-1])----- this is 0

macxsz · Answer

A. it raises an exception 
strong variable does not exist

kontra · Answer

If strong is a typo and is actually string, dummy = 333333333333333.0
So the answer is B: 0

lukaki · Answer

If there is: for character in strong:    Answer is A
If there is: for character in string:    Answer is B

DTL001 · Answer

Answer is B:

string = str(1/3)
dummy = ''
for character in string:
    dummy = dummy + character

print(dummy[-1])   # 3

# In python all types are classses
print(type(dummy))   # <class 'str'>

Siva_2022 · Answer

It outputs 0.
string=str(1/3)
print("string=",string)
dummy=''
for character in string:
    print("character=",character)
    dummy=character+dummy
print("dummy=",dummy)
print(dummy[-1])

CC_DC · Answer

A is right if the variable name us strong but if corrected to string (no sure if this a typo or intentional), then the result is 0.

seaverick · Answer

string = str(1/3)
dummy=''
for character in strong:
    dummy=character + dummy
print(dummy[-1])

Output -> NameError: name 'strong' is not defined
Ans A

zantrz · Answer

dummy = character + dummy: Adds the current character to the BEGINNING of the dummy string, effectively reversing the order of characters.

print(dummy[-1]): Prints the last character of the reversed string, which is the first character of the original string.

PCAP Exam - Question 87

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