What is the expected behavior of the following code?
x =3 % 1
y = 1 if x > 0 else 0
print(y)
What is the expected behavior of the following code?
x =3 % 1
y = 1 if x > 0 else 0
print(y)
The code assigns the result of the expression 3 % 1 to the variable x. The modulo operation 3 % 1 returns 0 because 3 divided by 1 leaves a remainder of 0. The next line uses a conditional expression to assign 1 to y if x > 0, otherwise it assigns 0. Since x is 0, the condition x > 0 evaluates to false, so y is assigned 0. Therefore, the code prints 0.
As tested in my IDE
C is correct
is correct