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Question 128

Assuming that the code below has been executed successfully, which of the following expressions will always evaluate to True? (Choose two.)

    Correct Answer: B, C

    Given the code snippet, random.random() generates a random float number in the range [0.0, 1.0), which means it is always less than 1. Therefore, the expression v1 < 1 will always evaluate to True. Additionally, random.choice([1,2,3]) selects a random element from the list [1, 2, 3], all of which are greater than 0. Therefore, the expression random.choice([1,2,3]) > 0 will also always evaluate to True. The option v1 == v2 is not correct because v1 and v2 will be different most of the time due to the nature of generating random numbers. Finally, len(random.sample([1,2,3],1)) > 2 is incorrect because random.sample([1,2,3],1) always returns a list of one element, making its length 1, which is not greater than 2. Therefore, the correct answers are B and C.

Discussion
macxszOptions: BC

B. v1 < 1 C. random.choice([1,2,3]) > 0

DezzoPalYeahOptions: BC

random.random() returns a float that is greater than 0 but less than 1. v1 = random.random() v1 will always be less than 1 So B is True random.choice([1,2,3]) returns 1,2, or 3. which is always greater than 0. C is True

stuartzOptions: BC

B & C >>> import random >>> v1 = random.random() >>> v2 = random.random() >>> print(v1) 0.17779831894224019 >>> print(random.choice([1,2,3])) 1 v1 will always be less than 1 random choice will always be one in the list and greater than 0

dicksonpwcOptions: BC

Ans A, as v1 = 0.054095873573811515, v2 = 0.8975891098469417. So v1 != v2. Then, return False Ans B, v1 =0.054095873573811515. so v1< 1. Then, return True Ans C, random.choice([1,2,3]) = 1. So 1 >0. Then, return True Ans D, len(random.sample([1,2,3],1)) = 1. So 1 < 2. Then, return False Correct Answer should be B and C