What is the expected behavior of the following code?
the_list = "alpha;beta;gamma".split(";")
the_string = ''.join(the_list)
print(the_string.isalpha())
What is the expected behavior of the following code?
the_list = "alpha;beta;gamma".split(";")
the_string = ''.join(the_list)
print(the_string.isalpha())
The code first splits the string 'alpha;beta;gamma' by the semicolon delimiter, resulting in the list ['alpha', 'beta', 'gamma']. Then, it joins this list into a single string 'alphabetaGamma' with an empty string as the separator. Finally, the isalpha() method is called on this new string, which checks if all characters in the string are alphabetic. Since 'alphabetaGamma' consists only of alphabetic characters, print(the_string.isalpha()) will output True.
D is the correct , the_string = ".join(the_list) should be : the_string = "".join(the_list) so it raises an exception
D is correct
Sorry the answer correct is A