What is the expected output of the following snippet?
What is the expected output of the following snippet?
The code contains a syntax error. Specifically, the comparison within the if statement uses a single equals sign (i % 2 = 0) which is incorrect for equality comparison in Python. It should use a double equals sign (i % 2 == 0). Therefore, the code will not run and will raise a syntax error. Hence, the expected output is that the code is erroneous.
In this case, the correct answer is A, because inside the if for comparing the result of the modulus must be if i % 2 == 0: .....
I wrote a few days ago. There are no identation or 'issues ==' typos in the exam.
This is true, I took the exam and failed. There are no typos or indentation issues.
how many new questions was on exam ?
maybe 20
thanks and good luck next time
should be if == answer: A. the code is erroneous
Answer is A because we have "if i % 2 = 0" and it should be "if i % 2 == 0" Even if we had if i % 2 == 0 having break command inside skips the else block
The answer is A because it says "i%2=0" which causes a a error. it should be "i%2==0"
Answer is A
a is correct since the equality operator is wrong
Notice that the following snippet is: if i%2=0: that raise a SyntaxError You would be right if the snippet were: if i % 2 == 0:
A is correct as the equality operator is wrong. It is supposed to be a == 5.
A is correct , for reason of invalid synthax
A is correct. == is required.
It will throw error while exe ution
Answer is 2 (with correction of code typo and indentation)
A. the code is erroneous There is no indentation error, however the line that has % 2 = 0 should be % 2 == 0
There are two major typos that I can see: 1) "if i % 2 = 0" should be "if i % 2 == 0" 2) The "if" and "else" statements aren't lined up correctly.
The second one isn't a typo. The else is part of the while, which gets executed the moment that you exit the loop.
answer is B
the answer is 2, I ran in IDE