PCAP Exam - Question 29

Question

What is the expected behavior of the following code?It will:.

Examice · Accepted Answer

B.

hackadocka · Answer

yield keyword expression is I (capital i), while for loop variable is i (small I). Function is erroneous.

Efren · Answer

>>> def f(n):
...     for i in range (1,n+1):
...             yield I
...
>>> print(f(2))
<generator object f at 0x0000013BA21A82A0>

ANswer is correct

TheNetworkStudent · Answer

if you try to loop through the generator, it will error. This won't happen because it's simply printed. Code is erroneous, but won't result in an error if executed in this manner.

Answer B is correct.

Ello2023 · Answer

Yield I is not the same as the variable name i. Which should mean runtime error.

zantrz · Answer

def f(n):
    for i in range(1,n+1):
        yield i

print(f(2)) #output: <generator object f at 0x000001C77ED4D000>
generator=f(2)
print(next(generator)) #output: 1
print(next(generator)) #output: 2
print(next(generator)) #output: StopIteration

vidts · Answer

answer is correct

ivanbicalho · Answer

This question is SO TRICKY. yield I, or yield X or yield ANYTHING, doesn't matter because in the code the undefined variable "I" is never reached. As the answer below from TheNetworkStudent, the answer is B.

mlsc01 · Answer

The NameError is not raised because the generator is not executed at all. It's defined and only its reference is used. If it is executed in a loop or comprehension or by using next() then only the NameError will be raised.

macxsz · Answer

B. print <generator object f at (some hex digits)>

PremJaguar · Answer

answer is c because variable names are case sensitive

CAPTAINKURK · Answer

yield automatically creates, __iter__() and next()  function. assuming it was yeild i. 
then to print, we would need print(next(f(2)))

natlal · Answer

def f(n):
    for i in range(1,n+1):
        yield i
print(f(2))                  #<generator object f at 0x00000220062CB140>

for x in f(2):
    print(x, end='')       #12

def f(n):
    for i in range(1,n+1):
        yield I
for x in f(2):
    print(x, end=' ')      #NameError: name 'I' is not defined

Oracleist · Answer

yield control the flow of a generator.
than if we use I instead of the variable name i, it will return an object that represent a generator.

G3n · Answer

The answers in the dumps are good to remember! The bulk of the exam questions are from these exam dumps. The questions with mistakes in them or missing : etc are in the exam but in the correct answer form, do remember the correct answers as well as the answers with the mistakes in the coding. There are a few questions that are slightly different but you can find the answers from the previous or next question/answers! Hope this helps!

PCAP Exam - Question 29

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