1z0-819 Exam - Question 40

Question

Given the code fragment:What is the result?

Examice · Accepted Answer

The code initializes two char variables 'd' and 'e' with values 100 and 'e', respectively. In the ASCII table, the value 100 corresponds to the character 'd' and 'e' corresponds to the value 101. In line 2, 'd' is converted to integer and assigned to 'x', so 'x' becomes 100. In line 3, 'e' is cast to an integer and assigned to 'y', so 'y' becomes 101. The sum of 'x' and 'y' is 201. Therefore, the output of the code will be 201.

Obalt · Answer

Correct answer is B

Obalt · Answer

There is a minor error on line 3. 
Should be int y = (int)e.  Then B is correct answer

RP384 · Answer

"int =" will fail

Jtic · Answer

char d = 100, e = 'e' ; // line 1
        int x = d ; // line 2
        int  y = (int) e; // line 3
        System.out.println ((char) x + (char) y) ;

Stavok · Answer

E is correct

Tested

[Removed] · Answer

E is correct.
int = won't compile

Bugmenot240411 · Answer

Correct answer is B 
i did run it and it print 201

1z0-819 Exam - Question 40

Discussion