Given:
What is the result?
Exam 1z0-819 All QuestionsBrowse all questions from this exam
Question 156
Correct Answer: A
The code will fail to compile because in a try-with-resources statement, the resource `reader` is effectively final. Once a BufferedReader object is initialized within the try-with-resources, it cannot be reassigned. In the provided code, after the first file is read, the code attempts to reassign `reader` to a new BufferedReader object for the second file, which is not allowed. As a result, a compilation error will occur.
Discussion
ASPushkinOption: A
In both cases reader1 is effectively final : BufferedReader reader1 = new BufferedReader(new FileReader("journaldev.txt")); try (reader1) { System.out.println(reader1.readLine()); //reader1 = Error effectively final } catch (IOException e) { System.out.println(reader1); } } or try (BufferedReader reader1 = new BufferedReader(new FileReader("journaldev.txt"));) { System.out.println(reader1.readLine()); //reader1 = Error effectively final } catch (IOException e) { }
d7bb0b2Option: A
Variables in try with resource are implicit final, so if you try to asing a new value in try block no compile time error.
OmnisumemOption: A
Tested: A. auto-closeable resource reader may not be assigned reader = new BufferedReader (new FileReader(file2)); ^ 1 error error: compilation failed
StavokOption: A
A is correct Exception in thread "main" java.lang.Error: Unresolved compilation problem: The resource reader of a try-with-resources statement cannot be assigned