Given:
What is the result?
Exam 1z0-819 All QuestionsBrowse all questions from this exam
Question 153
Correct Answer: A
The given code contains type mismatches and issues related to generics. The 'var' keyword in Java infers the type of the variable based on the right-hand side of the assignment, and since the ArrayList is created without a type parameter, it will be treated as an ArrayList of Object type. The method 'add' is adding both Integer and Float values to the list. However, the for-each loop in 'main' is expecting elements of type Integer. When the Float value is encountered, a ClassCastException will be thrown. Thus, the correct answer is that the program prints 3 4 and throws a ClassCastException.
Discussion
OmnisumemOption: A
Tested. No correct answer. But A is closest.
KiraguJohn
No answer as for loop is expecting objects and not Integer.
ASPushkinOption: A
Agreed that no answer correct. Old style List without generic diamond keeps Objects inside. It will be compile error : incompatible types, Object -> Integer throws exception. ------ But this code works : for(Object i : x) { System.out.println(i); }
d7bb0b2Option: A
No answer correct, code not comiple for this for(Integer i : x){} //expected objetct not integer. but if the line are modified like this: var x = new ArrayList<Integer>(); then throw thown: java.lang.ClassCastException: class java.lang.Float cannot be cast to class java.lang.Integer
dillemanOption: C
It does not compile as the for loop has Integer i : x. If we change this to for (Object i : x) then the output will be C: 3, 4, 3.14
belal97Option: A
if var x = new ArrayList<Integer>(); the correct answer is A
Samps
if we make the change then it fails to compile at the point of adding a double value