e,f,J,B are visible at line 1 because they are public and protected other will not because whether they are private or Default So correct is ABDH

tested. default/package variables won't be visible. and h is the parameter for the Foo class constructor, not for Bar's constructor.

public class Foo { static final int A = 0; public static final int B = 0; private static final int C = 0; int d = 0; protected int e = 0; public int f = 0; private int g = 0; public void foo(int h){ int i = 0; } } IN OTHER PACKAE ONLY ACCESS: public void foo(int j) { System.out.println(B); System.out.println(e); System.out.println(f); System.out.println(j); }

I tested this code: public class Bar extends com.foo.Foo{ @Override public void foo(int j){ System.out.println(super.B+" "+new Bar().e+" "+new Bar().f+ " "+ j); } public static void main(String[] args) { Bar bar = new Bar(); bar.foo(5); }} The output is: 0 0 0 5, so the correct answer: A B D H (with identifiers: e, f, j, B)

ABDH is correct

Answer: ABDH e: Protected, visible outside package by subclass only f: public j: overridden function's parameter B: public

update*

tested