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Question 154

Given:

What is the output?

The compilation fails due to an error in line 1.

I am an array

I am an object array

I am an object

Correct Answer: D

In the given Java code, the method analyze() with the parameter of type Object will be called. This is because in Java, arrays are objects, and therefore, the parameter nums which is of type int[] will be upcast to Object. Hence, the output will be 'I am an object.'

Discussion

OmnisumemOption: D

Tested: D.

d7bb0b2Option: D

arrays are object in java, so method call to object version overload method

APJ1Option: D

Tested: D

Ashan_OzlovOption: D

D Tested

[Removed]Option: D

D is correct.

StavokOption: A

Over cannot be resolved to a type A is correct

KiraguJohnOption: D

D is the correct answer