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Question 167

Given:

What is the result?

    Correct Answer: C

    In the given code, the variable 'x' is declared inside the try block and hence its scope is limited to the try block only. When the NumberFormatException is caught, the program attempts to print 'x' in the catch block, but 'x' is not in scope at this point, leading to a compilation error. Therefore, the correct answer is 'The compilation fails due to an error in line 2'.

Discussion
d7bb0b2Option: C

x not can be access in catch block

d7bb0b2Option: C

C: catch clause cannot see X create in try block

OmnisumemOption: C

Tested: C.

[Removed]Option: C

C is correct. x is out of scope in the catch block.

StavokOption: C

C is correct x cannot be resolved to a variable

KiraguJohnOption: C

C as x is not in the scope.