Given the code fragment:
What is the result?
Given the code fragment:
What is the result?
The code provided uses a for loop where the variable 'i' starts at 0 and runs until 'i' is less than 10. The loop increments 'i' after each iteration. Inside the loop, 'i' is pre-incremented (++i) before being printed. The pre-increment operator increases the value of 'i' by 1 before it prints. Thus, in each iteration, the loop prints 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. However, since the post-increment 'i++' occurs after the print within the loop, the sequence of values printed will be: 1 (i=1), 3 (i=2 then increment 3 to the print), 5, 7, 9, and stop when 'i' is incremented to 10. Therefore, the correct result is '1 3 5 7 9'.
D is correct 1- print 1 2- print 3 3- print 5 4- print 7 5 - print 9 then ++i => 10 finish
D is correct , cause print impar begin in 1 and finish when i = 10
Tested. D