Given the associated prefix value, which of the following is a valid host address?
Given the associated prefix value, which of the following is a valid host address?
172.16.224.255/18 is a valid host address. Within the subnet defined by the prefix /18, the network range for 172.16.224.255 would be 172.16.192.0 to 172.16.255.255. As a result, 172.16.224.255 falls within this range, and it is neither the network address nor the broadcast address for this /18 subnet. Thus, it is a valid host address.
Answer is C A) 172.16.224.255/18 -> valid host is range 172.16.192.1 - 172.16.255.254, so 172.16.224.255 is not valid host address. instead it is broadcast address. B) 255.255.255.255/32 -> obviously not a valid host address C) 224.1.2.1/8 -> Valid host is range 224.0.0.1 - 224.255.255.254 so it is valid host address D) 192.168.24.59/30 - Valid host is range 192.168.24.57 - 192.168.24.58. 192.168.24.59/30 is broadcast address.
Hi, your reasoning for discarding A is wrong. The range is correct:172.16.192.1 - 172.16.255.254. However, the IP 172.16.224.255 is not a broadcast address for the subnet 172.16.224.255/18 since it is not the last IP of the subnet (it is 172.16.224.255). It would be the broadcast address if the subnet was something like 172.16.224.0/24, but it's not. The C cannot be a valid host address because that range is reserved for multicast address. Therefore, the only correct answer is A
224 is used for multicast
The valid answer is A, because the start Network: 172.16.192.0/18 & Broadcast: 172.16.255.255 everything in between is valid host. the answer C is wrong because it's multicast address not host address. thank you,
To determine which of the given IP addresses is a valid host address within the subnet, we need to consider the subnet mask: 172.16.224.255/16 - MASK: 11111111.11111111.|11000000.00000000 - To determine if an IP address is a valid host address, we need to check if the host portion (the last 14 bits) is all zero or all ones. - HOST: 10101100.0001 0000.11|000000.11111111 - That's a valid host. 255.255.255.255/32 - That's a Broadcast. 224.1.2.1/8 - That range is reserved for multicast address. 192.168.24.59/30 - MASK: 11111111.11111111.11111111.111111|00 - To determine if an IP address is a valid host address, we need to check if the host portion (the last 2 bits) is all zero or all ones. - HOST: 1100 0000.10101000.00011000.001110|11 - That's a Broadcast. So, the correct answer is A.
I don't think "C" is a valid answer. As we only use subnetting for class A, Class B and Class C IP range. 224.X.X.X is useful for multicasting purpose (Class-D)
Both A&C should be valid