How many subnets and host addresses are obtained by subnetting network 201.148.26.0/24 using a /26 subnet mask?
How many subnets and host addresses are obtained by subnetting network 201.148.26.0/24 using a /26 subnet mask?
Subnetting a /24 network with a /26 subnet mask results in 4 subnets, as each subnet is formed by borrowing 2 bits from the host portion (2^2 = 4). Each /26 subnet has 64 addresses (2^(32-26) = 64), but 2 addresses in each subnet are reserved (1 for the network address and 1 for the broadcast address), leaving 62 usable host addresses per subnet.
4 subnet , 64 address - 2 for broadcast and network , should be 62. Answer should be C
Answer should be C. Network & Broadcast addresses should be removed from count
The answer should be "C".
Glad I'm not the only one saying it should be C
should be C
C is the correct answer.
Should be C. 64-2 = 62
question doesn't specify usable host, so it could be 4-64
C is the correct answer. 62 hosts.
It asked number of hosts for /26, it should be 64. Number of useable hosts is 62. IMHO, A is correct.