Which of the following commands puts the output of the command date into the shell variable mydate?
Which of the following commands puts the output of the command date into the shell variable mydate?
To assign the output of the command date to the shell variable mydate, the correct syntax involves using command substitution. Command substitution in shell scripting is achieved by placing the command within $(...). The command '$(date)' executes the date command and returns its output, which is then assigned to the variable mydate. Therefore, using the syntax mydate="$(date)" correctly captures the current date and time and stores it in the variable mydate.
mydate="$(date)"
DESKTOP-KKVDTQ1:~$ mydate="date" DESKTOP-KKVDTQ1:~$ $mydate Tue Apr 30 00:31:01 EEST 2024 DESKTOP-KKVDTQ1:~$ mydate="$(date)" DESKTOP-KKVDTQ1:~$ $mydate Tue: command not found DESKTOP-KKVDTQ1:~$ uname -a Linux DESKTOP-KKVDTQ1 5.10.16.3-microsoft-standard-WSL2 #1 SMP Fri Apr 2 22:23:49 UTC 2021 x86_64 x86_64 x86_64 GNU/Linux
DESKTOP-KKVDTQ1:~$ mydate="date" DESKTOP-KKVDTQ1:~$ $mydate Tue Apr 30 00:31:01 EEST 2024 DESKTOP-KKVDTQ1:~$ mydate="$(date)" DESKTOP-KKVDTQ1:~$ $mydate Tue: command not found
Correct is A: [dawoud@server ~]$ mydate="$(date)" [dawoud@server ~]$ $mydate bash: Mi: Befehl nicht gefunden... [dawoud@server ~]$ mydate="date" [dawoud@server ~]$ $mydate Mi 25. Sep 17:59:24 CEST 2024 [dawoud@server ~]$
root@test-srv-ubuntu-2204:~# mydate="$(date)" root@test-srv-ubuntu-2204:~# echo $mydate Fri Nov 29 06:36:20 PM UTC 2024 root@test-srv-ubuntu-2204:~# mydate="$(date)" root@test-srv-ubuntu-2204:~# echo $mydate Fri Nov 29 06:36:20 PM UTC 2024 root@test-srv-ubuntu-2204:~# mydate="$(date)" root@test-srv-ubuntu-2204:~# echo $mydate Fri Nov 29 06:36:20 PM UTC 2024 root@test-srv-ubuntu-2204:~# mydate="date" root@test-srv-ubuntu-2204:~# echo $mydate date
mydate="$(date)"