Given the following routing table:
How would an outgoing packet to the destination 192.168.2.150 be handled?
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Question 135
Correct Answer: B
Given the routing table, a packet destined for 192.168.2.150 will match the route with the destination 192.168.2.0, which has a genmask of 255.255.255.0. This means it covers all IP addresses from 192.168.2.0 to 192.168.2.255. The route indicates that packets within this range should be handled by the device eth0 with no need to pass through another router, as indicated by the absence of an associated gateway for this route. Therefore, the packet would be directly transmitted on the device eth0.
Discussion
stef_88Option: E
Correct Answer is E. 192.168.2.0 is not directly connected, so packet will be transfered to gateway(router 192.168.1.1) via eth0 that is on connected subnet 192.168.1.0
kuma69Option: B
Surely this does not need to go through a router so: B. It would be directly transmitted on the device eth0.
Borbz
the eth0 is on the 192.168.1.x, you can see it because it has default gateway 0.0.0.0. so to reach 192.168.2.x it needs to go through a router or L3'switch, and you can see on the routing table there is a static routing advertising 192.168.2.x though 192.168.1.1 which can be reached through the ETH0.
EliteAllenOption: B
B. It would be directly transmitted on the device eth0. This is the correct answer because the routing table indicates that the network 192.168.2.0/24 is directly accessible via the eth0 interface, so the packet would be transmitted directly on this interface without needing to be passed to a router.