What is the output of the following command sequence?
for token in a b c; do
echo -n "$token ";
done
What is the output of the following command sequence?
for token in a b c; do
echo -n "$token ";
done
The command sequence iterates over the tokens 'a', 'b', and 'c'. The 'echo -n' command prints each token followed by a space, without a newline at the end. Therefore, the output will be 'a b c '.
This is incorrect. Replace the first line with "for token in "a " "b " "c " yada yada B is the right answer. As shown the answer is abc
The given answer is correct
Here the output for token in a b c; do echo -n "$token "; done There is a space between token and ", if no space, then the answer is abc.