Click the Exhibit button.

Referring to the exhibit, which path would traffic passing through R1 take to get to R4?
Click the Exhibit button.
Referring to the exhibit, which path would traffic passing through R1 take to get to R4?
Considering the OSPF cost of each path, the goal is to find the path with the lowest total cost. The paths from R1 to R4 and their total costs are as follows: R1 -> R3 -> R4 with a cost of 5 + 10 = 15, R1 -> R2 -> R4 with a cost of 15 + 10 = 25, and R1 -> R2 -> R3 -> R4 with a cost of 15 + 5 + 10 = 30. Therefore, the shortest and most cost-effective path is R1 -> R3 -> R4 with a total cost of 15.
The OSPF cost is carried in the LSAs that are exchanged within an OSPF area. When a router calculates the cost to a destination it uses the cost of the exit interface of each router in the path to the destination.
Anyone can explain this for me?
only see the outgoing interfaces
C is the shortest path