Consider the following pseudo code:
1 Begin
2 Read Time
3 If Time < 12 Then
4 Print(Time, "am")
5 Endif
6 If Time > 12 Then
7 Print(Time 12, "pm")
8 Endif
9 If Time = 12 Then
10 Print (Time, "noon")
11 Endif
12 End
If the test cases Time = 11 and Time = 15 were input, what level of decision coverage would be achieved?
For decision coverage, each possible outcome of every decision must be exercised at least once. The pseudo code contains three decisions: Time < 12, Time > 12, and Time = 12. For the test case Time = 11, the outcomes are True for Time < 12, and False for both Time > 12 and Time = 12. For the test case Time = 15, the outcomes are False for Time < 12, True for Time > 12, and False for Time = 12. Thus, the True outcomes for Time < 12 and Time > 12, and the False outcomes for all three decisions (Time < 12, Time > 12, Time = 12) are covered, giving us 5 out of 6 possible decision outcomes. Therefore, the decision coverage is 83% or 5/6.
I think 4/6 is correct C.
can someone please explain why the answer is D?