If the IPv4 address of a host on a local area network (LAN) is 192.168.1.1/30, which of the following destination IPv4 addresses can be carried in data packets that the host can decapsulate?
If the IPv4 address of a host on a local area network (LAN) is 192.168.1.1/30, which of the following destination IPv4 addresses can be carried in data packets that the host can decapsulate?
The IPv4 address 192.168.1.1/30 implies a subnet mask of 255.255.255.252. This creates a subnet range from 192.168.1.0 to 192.168.1.3, where 192.168.1.0 is the network address and 192.168.1.3 is the broadcast address. The usable IP addresses in this subnet are 192.168.1.1 and 192.168.1.2. Since the question asks for a destination IPv4 address that can be carried in data packets that the host can decapsulate, the host at 192.168.1.1 should be able to decapsulate packets destined to itself and 192.168.1.2. Therefore, 192.168.1.2 is the correct answer.
If the host is decapsulating a packet, I think is becasue it's receiveing it from the another neighbor on the same subnet. So, the packet was orioginally sent by the neighbor with an origin IPv4 address: 192.168.1.2 and destination IPv4 address: 192.168.1.1.