Refer to the graphic.
Both switches are operating using STP. With exception to those shown, all other default parameters have been maintained. Which port will be blocked?
Refer to the graphic.
Both switches are operating using STP. With exception to those shown, all other default parameters have been maintained. Which port will be blocked?
STP (Spanning Tree Protocol) ensures that there is no loop in the network by blocking certain redundant paths. Considering both Switch A and Switch B are configured as STP root primary, they will undergo root bridge selection based on their Bridge ID. The Bridge ID is composed of a priority value and the switch's MAC address. Without knowing the MAC addresses, the switch with the lowest MAC address will become the root bridge. Assuming default STP priority values, and that Switch A has a lower MAC address than Switch B, Switch A will become the root bridge. Consequently, all of its ports will remain in forwarding state. Switch B will have its port G0/0/2 blocked to prevent a loop, as this is how STP prevents loops by blocking the redundant link's port with the higher number on the non-root bridge (Switch B in this case). Thus, port G0/0/2 of switch B will be blocked.
Tha MAC address of each switch is missing. There is no way to know the answer without that.
I do not understand the question
i think the switch 'A' have mac address : 00:00...:AA and switch 'B' 00...:BB
I think this might be mistaken
may be all ports are blocked - during th intial process: https://support.huawei.com/enterprise/en/doc/EDOC1000142081/9e9923f2/stp-topology-calculation After STP is enabled on all devices on a network, all devices initially consider themselves as the root bridge. They only transmit and receive BPDUs and do not forward user traffic, and all ports on the devices are in Listening state