According to the configuration on R1 shown in the following figure, the two PCs can correctly access the ISP network.
According to the configuration on R1 shown in the following figure, the two PCs can correctly access the ISP network.
The configuration on R1 looks correct for enabling PCs in the 192.168.0.0/24 network to access the ISP network at 200.100.1.1. Specifically, an access control list (ACL) has been defined and applied for packets originating from the internal network (192.168.0.0/24), the NAT rule is correctly set using the 'easy-ip' parameter to allow internal IP addresses to be translated to the public IP address configured on the outgoing interface, and a static default route is configured to forward any unknown packets to the ISP's gateway. Therefore, the PCs should be able to access the ISP network successfully.
No need a 'easy ip' parameter in the configuration.
correct B
It's correct nat acl rule is outbound so it allows the packets from the inner network.
Correct answer is B easy ip is configure with “nat outbound “acl num” “ no parameter such as easy ip after acl number