If a network's address is 192.168.1.0, the broadcast address of the network is 192.168.1.255.
If a network's address is 192.168.1.0, the broadcast address of the network is 192.168.1.255.
For the network address 192.168.1.0 with the commonly used default subnet mask of 255.255.255.0 (or /24), the broadcast address is indeed 192.168.1.255. This is because, in this subnet, the last address (with all host bits set to 1) is designated as the broadcast address.
Shouldn't it be false if subnet is not defined? It could be 192.168.2.255 as well if subnet is /23 or different if there is different subnet
Shouldn't it be false if subnet is not defined? It could be 192.168.2.255 as well if subnet is /23 or different if there is different subnet
Yeah don't get it. If network ADDRESS is 192.168.1.0 and IE mask is /25, its broadcast is .127.
even if the mask was /25 192.168.1.255 would still be a broadcast address for 192.168.1.128/25 subnet so ..
but questionis is about network 192.168.1.0 not 192.168.1.128, so....