Refer to the exhibit.
The exhibit shows the SD-WAN rule status and configuration.
Based on the exhibit, which change in the measured latency will make T_MPLS_0 the new preferred member?
Refer to the exhibit.
The exhibit shows the SD-WAN rule status and configuration.
Based on the exhibit, which change in the measured latency will make T_MPLS_0 the new preferred member?
The SD-WAN service uses a latency-based priority for selecting the preferred member. Currently, the latencies are 101.349 ms for T_INET_0_0, 151.278 ms for T_INET_1_0, and 200.984 ms for T_MPLS_0. For T_MPLS_0 to become the preferred member, its latency must be significantly lower than the other members. If T_MPLS_0 has a latency of 80 ms, it will be lower than T_INET_0_0's current latency of 101.349 ms, making T_MPLS_0 the new preferred member.
13) The exhibit shows the SD-WAN rule status and configuration. Based on the exhibit, which change in the measured latency will make T_MPLS_0 the new preferred member? pag 203 guide 7.2 B. When T_MPLS_0 has a latency of 80 ms. Latenci en inet_0 is 101.349/1.10=92.14
A. - wrong because INET_1_0 will still win MPLS_0 B. correct because 80ms will be better from the corrected metric of INET_0_0 C. Wrong because INET_0_0 has better priority D. wrong because 100ms will be worst from the corrected metric of inter_0_0
One question. What formula is made to give this result? 80ms. Thanks,
B is correct. Refer to Link Cost Threshold section in SD WAN 7.2
B es la correcta