Refer to the exhibit.
The exhibit shows the SD-WAN rule status and configuration.
Based on the exhibit, which change in the measured packet loss will make T_INET_1_0 the new preferred member?
NSE7_SDW-7.2 Exam QuestionsBrowse all questions from this exam
NSE7_SDW-7.2 Exam - Question 67
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7 commentsccie8122Option: D
Oct 31, 2024Since the threshold is 0% and T_INET_1_0 (member 5) has the highest priority, as long as the other two links have the same or higher packet loss as T_INET_1_0, T_INET_1_0 wins the tie breaker.
MellonOption: D
Oct 4, 2024link-cost-threshold 0 = strict metric comparison priority-member 5 4 3, T_INET_1_O is hightest priority
jebusrunsOption: D
Oct 4, 2024Guide 7.2
f9dcb3eOption: D
Oct 30, 2024link-cost-threshold 0 = strict metric comparison priority-member 5 4 3, T_INET_1_O is hightest priority
kappa915Option: D
Nov 17, 2024D is correct, check ccie8122's answer
aa0v1snjr9
Nov 22, 2024continue to not understand. because seems that the answer should be A because win tie breaker... but is signed D.. where itàs written all members have the same packet loss..
aa0v1snjr9
Nov 18, 2024i don't understand the answer it's D. When all three members have the same packet loss??
0x194
Dec 17, 2024- If you set `link-cost-threshold` to `0`, then FortiGate performs a strict metric comparison -> link-cost-threshold(0) - The member with the best metric becomes the preferred (tiebreaker) -> priority-members 5 3 4 All members need to have the same packet loss; otherwise, T_INET_1_0 (5 T_INET_1_0) can't get the preferred member through priority (tiebreaker). Study Guide Page 202
0x194
Dec 17, 2024Therefore, the correct answer is D: When all three members have the same packet loss.