nse8_812 Exam - Question 9

Question

An HA topology is using the following configuration:Based on this configuration, how long will it take for a failover to be detected by the secondary cluster member?

Examice · Accepted Answer

In the given configuration, the heartbeat interval (hb-interval) is set to 3. This is equivalent to 300 milliseconds (ms) because the default heartbeat interval is generally taken as 100 ms multiplied by the set interval value. The hb-lost-threshold is 2, which means the failover will be detected after 2 missed heartbeats. Therefore, the total time to detect a failover will be 2 times the hb-interval, which is 2 x 300 ms = 600 ms. Hence, the correct answer is 600 ms.

Noidea · Answer

A:  Default interval = 100ms.  It can miss 2.  So 2x300ms = 600ms

Davidrichard · Answer

https://docs.fortinet.com/document/fortigate/7.4.0/administration-guide/489324/failover-protection

pwatchpk · Answer

A is correct.

ama6 · Answer

Sorry guys Noidea is correct the AW is A

pitz · Answer

A is correct

ama6 · Answer

B  is correct
 
in the exhibit HA heartbeat interval is 100ms and  before a failover is detected is 2
2x100= 200ms

BozoPin · Answer

Yes, he is...

node345 · Answer

hb-interval = 3 (3x100ms)
hb-lost-threshold = 2 
2 x 300ms = 600 ms . A is correct

nse8_812 Exam - Question 9

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