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101 Exam - Question 58


A virtual server is defined per the charts. The last five client connections were to members C, D, A, B, B. Given the conditions shown in the above graphic, if a client with IP address 205.12.45.52 opens a connection to the virtual server, which member will be used for the connection?

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Correct Answer: DE

The virtual server uses the Least Connections load balancing method, which chooses the member with the fewest active connections. Among the available members, E (172.16.20.5:80) has the least number of current connections at 18, compared to B and D, which have 42 and 22 connections respectively. Therefore, the member used for the connection will be E.

Discussion

4 comments
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kokodokoOption: E
Apr 20, 2021

The load balancing method is Least Connections, which choose the member that has the least number of active connections. In this case, I think the true answer is E, because this member has least number of current connections.

dkuboOption: D
May 14, 2021

The priority group is set to less than 2. The status shows that A and C are unavailable, so the packet is forwarded to B and D. Comparing these two, D is the one with the Least Connections.

KZM
May 1, 2023

Could you please explain to me why option "E" is excluded in comparison?

flavioaragonOption: B
Feb 21, 2021

B has no priority and received only two connections? Shouldn't I get two more?

juantronOption: D
Jan 15, 2022

D, as dkubo says, because "less than 2" means you only can select two active members with higher priority.

abdelrahmanismail239
Oct 21, 2023

Less than means the minimum number of members that must be available in one priority group before system direct traffic to lower priority group members so I think answer Is E not D