A computer forensics investigator is analyzing a hard disk drive (HDD) that is suspected to contain evidence of criminal activity. The HDD has 20,000 cylinders, 16 heads, and 63 sectors per track, with each sector having 512 bytes. During the analysis, the investigator discovered a file of 1.5KB in size on the disk. How many sectors are allocated for the file, and what could be the consequences of such allocation for the investigation?
A file size of 1.5KB is equivalent to 1.5 * 1024 bytes, which equals 1536 bytes. Since each sector on the HDD is 512 bytes, the number of sectors required to store 1536 bytes is 1536 / 512, which equals 3 sectors. This allocation could potentially increase the retrieval time due to the increased sector overhead.
1.5KB = 1.5 * 1024 bytes = 1536 bytes Since each sector is 512 bytes, we calculate the number of sectors required to store 1536 bytes: Number of sectors = 1536 bytes / 512 bytes per sector = 3 sectors C makes the most amount of sense
C > It is an important determinant of the time taken for accessing data. As the hard disk uses bits for disk or data management, the overhead size must be minimized to maximize efficiency. A file on a disk stores data in a contiguous series for optimal space usage, while the system allocates sectors for the file according to its size.
1.5kB = 1500 bytes / 512 bytes per sector = 2.9296875 sectors