312-49v10 Exam QuestionsBrowse all questions from this exam

312-49v10 Exam - Question 112


What will the following command accomplish?

C:\ nmap -v -sS -Po -data_length 6600 0-packet_trace

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Correct Answer: AD

The command specified uses nmap to perform a SYN scan with a packet size of 6600 bytes, which is significantly larger than the standard Maximum Transmission Unit (MTU) of 1500 bytes. This configuration forces packet fragmentation. The options included such as -v for verbosity, -sS for SYN scan, -Po to disable ping scans, and --packet_trace to enable packet tracing, all contribute to testing the ability of a router to handle fragmented packets.

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jjweust
Apr 19, 2022

There are only two nmap commands referenced in CHFI v10 manual pg. 495-496. nmap -sU and nmap -sT. For what it's worth, an nmap command like this isn't even tested on CEH.

[Removed]
Oct 12, 2023

yeah, they're really pushing hard for us to take their CEH. Almost a quarter of the questions i saw here is actually more relevant for CEH lol

aqeel1506Option: D
Jul 17, 2024

The correct answer is D. Test the ability of a router to handle fragmented packets. The command uses the nmap tool to perform a scan with the following options: -v: increases verbosity -sS: performs a SYN scan (half-open TCP connection) -Po: disables ping scans and OS detection <ip>: specifies the target IP address --data_length 6600: sets the packet size to 6600 bytes, which is larger than the standard MTU (Maximum Transmission Unit) of 1500 bytes, forcing packet fragmentation --packet_trace: enables packet tracing By setting the data length to 6600 bytes, the scan will send packets that need to be fragmented, allowing you to test the router's ability to handle fragmented packets.