In a FAT32 system, a 123 KB file will use how many sectors?
In a FAT32 system, a 123 KB file will use how many sectors?
In a FAT32 system, a typical sector is 512 bytes. To determine the number of sectors a 123 KB file will use, the file size must be converted to bytes (123 KB = 123 * 1024 = 125952 bytes). Dividing this by the sector size gives 125952 / 512 = 246 sectors. None of the provided options correctly represent 246 sectors.
512Bytes make 1 Sector ; 123KB=123*1024=125952Bytes >> 125952/512 = 246 Sectors. No answer in this case
There is an error in this question. All the answer are wrong.
Wrong question
In a FAT32 file system, each sector is typically 512 bytes (0.5 KB) in size. To calculate the number of sectors used by a 123 KB file, you can divide the file size by the sector size: 123 KB (file size) ÷ 0.5 KB (sector size) = 246 sectors However, since FAT32 uses cluster allocation, which groups sectors into clusters, the actual number of sectors used will be rounded up to the nearest cluster boundary. The default cluster size for FAT32 is 8 sectors (4 KB). So, the 246 sectors will be rounded up to: 246 sectors ÷ 8 sectors/cluster = 25 clusters Therefore, a 123 KB file will use 25 clusters, which is equivalent to 25 × 8 = 200 sectors. so the answer is B