312-49v10 Exam QuestionsBrowse all questions from this exam

312-49v10 Exam - Question 133


Given the drive dimensions as follows and assuming a sector has 512 bytes, what is the capacity of the described hard drive?

22,164 cylinders/disk

80 heads/cylinder

63 sectors/track

Show Answer
Correct Answer: A

The drive capacity can be calculated based on the provided dimensions using the following formula: Capacity (in bytes) = Number of cylinders × Number of heads × Number of sectors per track × Bytes per sector. Plugging in the given values, we have: Capacity = 22164 cylinders × 80 heads × 63 sectors/track × 512 bytes/sector. This results in Capacity = 22164 × 80 × 63 × 512 = 57,193,758,720 bytes. To convert bytes to gigabytes, we use the following conversions: 1 kilobyte (KB) = 1,024 bytes, 1 megabyte (MB) = 1,024 KB, and 1 gigabyte (GB) = 1,024 MB. Therefore, the capacity in gigabytes is 57,193,758,720 bytes ÷ 1,024 B/KB ÷ 1,024 KB/MB ÷ 1,024 MB/GB ≈ 53.26 GB.

Discussion

5 comments
Sign in to comment
vrocheOption: B
Dec 18, 2021

The real answer is 57.19 GB

Eggy_lin
Mar 3, 2022

1KB=1024 B

ManzerOption: B
Mar 11, 2023

Using the formula: Capacity = (Number of cylinders) x (Number of heads) x (Number of sectors) x (Sector size) Converting the number of cylinders, heads, and sectors: 22,164 cylinders/disk = 2^32 - 1 cylinders 80 heads/cylinder = 2^7 heads 63 sectors/track = 2^6 - 1 sectors Therefore, the capacity of the hard drive is: (2^32 - 1) x (2^7) x (2^6 - 1) x 512 bytes/sector = 57.27 GB So the answer is (B) 57.19 GB.

torabi123Option: A
Nov 5, 2023

Capacity (in bytes) = Number of cylinders × Number of heads × Number of sectors per track × Bytes per sector Given the drive dimensions: Number of cylinders/disk = 22164 Number of heads/cylinder = 80 Number of sectors/track = 63 Bytes per sector (standard sector size) = 512 bytes Plug these values into the formula: Capacity = 22164 cylinders × 80 heads × 63 sectors/track × 512 bytes/sector Now, calculate the capacity: Capacity = 22164 × 80 × 63 × 512 = 57,193,758,720 bytes To express this capacity in more common units: 1 kilobyte (KB) = 1,024 bytes 1 megabyte (MB) = 1,024 KB 1 gigabyte (GB) = 1,024 MB So, the capacity of the described hard drive is approximately: 57,193,758,720 bytes ÷ 1,024 B/KB ÷ 1,024 KB/MB ÷ 1,024 MB/GB ≈ 53.26 GB

ElbOption: A
May 7, 2024

57,193,758,720 bytes bytes = 53.265838623 gigabytes https://www.unitconverters.net/data-storage/byte-to-gigabyte.htm

DumasOption: A
Jun 17, 2024

A is correct because Bytes to Gigabytes is 53