You want to add an additional maintenance user on the PSM for SSH.
How can you accomplish this if InstallCyberarkSSHD is set to Integrated?
You want to add an additional maintenance user on the PSM for SSH.
How can you accomplish this if InstallCyberarkSSHD is set to Integrated?
To add an additional maintenance user on the PSM for SSH when InstallCyberarkSSHD is set to Integrated, you should create a local user and name them psmpmng<number>. This naming convention aligns with the requirements for creating maintenance users in an integrated setup for the PSM for SSH. Therefore, the correct answer is to create a local user called psmpmng<number>.
C should be correct but the path to sshd_config file is /etc/ssh/sshd_config that makes B a better answer
The annoying typo in the path to the sshd_config file (the correct path is /etc/ssh/sshd_config as others have stated) makes this question a little confusing however proxymng is already created and idetified automatically, therefore creating a proxymng<number> user may also work however that's not how the question reads therefore I beleive the answer is C. for an integrated configuration specifically. https://docs.cyberark.com/PAS/13.0/en/Content/PASIMP/Administrating-the-PSMP.htm#:~:text=Create%20a%20maintenance%20user%20when%20InstallCyberArkSSH%20is%20set%20to%20Integrated%3A
The Correct is C
In addition to the wrong path in answer C, the "Allowgroups" parameter does not exist in the Hardening of the sshd_config file: https://docs.cyberark.com/PAS/13.2/en/Content/PAS%20INST/Before-Installing-PSMP.htm#_Ref456888943:~:text=After%20installation%20and%20hardening%2C%20in%20the%20sshd_config%20file%3A
Ans : B in C the correct config is /etc/ssh/sshd_config
C is correct
https://docs.cyberark.com/PAS/13.2/en/Content/PASIMP/Administrating-the-PSMP.htm#Createamaintenanceuser
C is correct
Abs: B https://docs.cyberark.com/Product-Doc/OnlineHelp/PAS/Latest/en/Content/PASIMP/Administrating-the-PSMP.htm?tocpath=Administrator%7CComponents%7CPrivileged%20Session%20Manager%20for%20SSH%7C_____3
The correct answer is C