Refer to the exhibit. R2 has two paths to reach 192.168.13.0/24, but traffic is sent only through R3.
Which action allows traffic to use both paths?
Refer to the exhibit. R2 has two paths to reach 192.168.13.0/24, but traffic is sent only through R3.
Which action allows traffic to use both paths?
To enable traffic to use both paths in EIGRP, it's necessary to use the variance command to allow unequal cost load balancing. The feasible distance (FD) of the current best path (R3) is 1075200, and the FD of the second best path (R1) is 2611200. For EIGRP to use both paths, the variance must be set to a value higher than the ratio of these two FDs (2611200 / 1075200), which is approximately 2.4. Therefore, configuring the variance to 4, as suggested, will allow EIGRP to consider both paths for load balancing.
Answer = A Explanation: Feasible Distance of R3 (successor) = 1075200 Feasible Distance of R1 (feasible successor) = 2611200 Calculation: 2611200 / 1075200 = 2.4 So we need a Variance value higher than 2.4 for unequal cost load balancing to work.
The reason the given answer A is correct and why its not B. If we want to enable load balancing we have to use the following formula: FD of feasible successor < FD of successor * multiplier So we can work out that FD of feasible successor (R2) / FD of successor (R3) = 2.4 So the multiplier - or variance needs to be more than 2.4 - which means only answer A is correct.
The given answer is correct
The given answer is correct
The given answer is correct
I do not understand The successor has an FD of 1075200 The feasible successor has an RD of 281600 so the feasibility condition is met ...why should we manipulate the variance? maybe there is a missing zero in the RD of the Feasible successor?
Feasibility isn't the issue. R3 is the BEST route, so it's the only route used. Unless we change the variance. With variance 4, we can use any route where the FD is not greater than 4 times 1075200. (Variance 2 wouldn't be high enough in this case.)
THE RD is second number in bracket not the first.
The correct answer is: A
A is correct