Exam 200-301 All QuestionsBrowse all questions from this exam
Question 489

Refer to the exhibit. What is the subnet mask of the route to the 10.10.13.160 prefix?

    Correct Answer: D

    The subnet mask of the route to the 10.10.13.160 prefix is 255.255.255.248. This corresponds to a /29 subnet, which is evident from the routing table entry indicating a /29 mask. This is the correct subnet mask for that specific route.

Discussion
dozer86Option: D

D THE DESTINATION IS THE NETWORK 10.10.13.160 WITH MASK /29 WHICH IS THE ANSWER D. THE OTHER ROUTES DO NOT COVER THE NETWORK.160

BarkingSpiderOption: A

They are trying to trick us. Of course a /29 = 255.255.255.248. But the question: "What is the subnet mask of the route to the 10.10.13.160 prefix?" ...key word is ROUTE. It is not asking what is the mask of the 10.10.13.160 /29. There is a ROUTE to that subnet, and it is asking for the mask of that ROUTE. The ROUTE is 10.10.10.1 (the IP of g0/0), and that IP is part of the 10.10.10.0 /28 network. And we all know that a /28 mask is 255.255.255.240. Therefore the correct answer is A.

CertBuster

I strongly dislike how Cisco insists on us divining such complex meanings from their questions. It defeats the point of a technical examination when half of the questions require such deep examination. With that said, I disagree. 10.10.10.1 is *not* the IP of g0/0; it's the IP of the next hop. 10.10.10.0/28 is the subnet connected to g0/0; the route for the 10.10.13.160 prefix is recursive, and resolves to the interface on which that subnet is connected. A *prefix* is just another word for a subnet, so the question is really asking what is the mask of the route to 10.10.13.160 subnet is. The *route* is the entry in the routing table, not the next hop, or the subnet address on which the next hop resides. It must therefore be D.

1stAid

A host route is still a route. Highest prefix wins. So D for me

raul_kaponeOption: D

- Analyzing the subnet: 10.10.13.144/28 - Last octet: .144 = 1001/0000 - Range of addresses in this subnet: 10.10.13.144/28 ... 10.10.13.159/29 - So, 10.10.13.144/28 never reaches to the 10.10.13.60 route.

JulesAZOption: D

The answer just has to be D. Certbuster reflects my sentiments fully....... If you have to spend 3 minuted understanding what the question is trying to ask due to CISCO preferring to present questions in a foreign language the test needs to be a whole lot longer than 2 hours, thats without factoring in the 'sims' these days... DDDDDDDDD

kenkariOption: D

The given answer is correct; stop searching for the 'squaring of the circle.' It doesn't have such a philosophical interpretation as some are making it out to be. The correct answer is D.

CobramagoOption: D

the question is: ¿what is the "subnet mask"? so, The subnet mask for a /29 block is 255.255.255.248 correct answer: D

kylepttOption: D

/29 ans is D

e072f83Option: D

D = correct

lennylopesOption: D

/29 is 255.255.255.248 or /5 in the last octet, which is 11111000, which is 248.

SeMo0o0oOption: D

D is correct

a67c04aOption: A

It´s A for me

JunsK1eOption: D

Given answer is correct

YinxsOption: D

THe route is the record ""O 1010.13.160/29 [110/2] via 10.10.10.1...", It's not specific to the ip of next hop. So the network mask of the route is 29.

VarDavOption: D

So many wrong answers in the comments

tubirubsOption: A

f$ck this DUMP! lol. another question wrong....... i dont know. if anyone try the ccna 200-301 only for this dump questions, you spend your money!

PerryThePlatypus

Mate, count carefully: /29 translates to 11111111.11111111.11111111.11111000, which is 255.255.255.248 because it's 128+64+32+16+8, totaling 248

bymrdasOption: D

The answer is D

zbeugene7Option: A

The correct answer is A, because the route for the prefix 10.10.13.160/29 is 10.10.10.0/28. Please you can't argue that 10.10.13.160 is the route , because this is not the route this is destination prefix, therefore the next ho is "the route" , in layman terms a path to reach 10.10.13.160/29 network. Therefore the mask for the route is that of 28 bits long, that is 255.255.255.240.