Refer to the exhibit. With which metric was the route to host 172.16.0.202 learned?
Refer to the exhibit. With which metric was the route to host 172.16.0.202 learned?
The route to host 172.16.0.202 is learned through the OSPF route, which has a subnet of 172.16.0.128/25. In this context, the term 'metric' refers to the cost associated with the route, which in this case is 38443. The OSPF route provides the most specific match for the IP address 172.16.0.202, as it falls within the range 172.16.0.129 to 172.16.0.254, making 38443 the correct metric value.
I'm assuming by metric it means to ignore the 110 OSPF AD and select the cost. A is wrong because the Static route doesn't reach 172.16.0.202 B is wrong because that is the OSPF AD not metric. Which leaves C/D... Host - 172.16.0.202 falls under OSPF 172.16.0.128/25 202 in binary 11001[100] .200 - .207 192 in binary 11000[000] .192 - .199 Which means the host can't reach the EIGRP route therefore the OSPF route is used and has a metric of 38443
The static route DOES reach the host ... 172.16.0.1 - 254, BUT the keyword is "LEARNED" a STATIC route isn't l"learned" so that leaves us with the closed network route that was learned dynamically....hence 172.16.0.128/28 (172.16.0.129 - 254 hosts) OSPF
It's not really important here, what we have to notice is which route checks the longest prefix match algorithm. The static route doesn't match this algorithm as much as the OSPF one
Key word here is "metric". The answer would have been 110 if the question asked about the Administrative Distance (AD). OSPF was the preferred route in this instance because of the longest prefix match.
i had this question in the exam
when was your exam ? did you see a lot of questions here in the exam ? please tell me
C. Given answer is correct. /29 is 192-200, so not inclusive, leaving /25 which has a metric of 38443
C. 38443. Because /25 is the highest prefix to reach 172.16.0.202. So just take the metric form there.
but it doesn't reach 172.16.0.202, learn some subnetting
It does reach to 172.16.0.202, lol
Before being rude and telling people to learn some subnetting, start with yourself. 172.16.0.128/25 Number of hosts : 126 First host : 172.16.0.129 Last host : 172.16.0.254 So...how it doesn't reach 172.16.0.202 ?
regardless of "learned" or not.. prefix takes precedence over AD.. even if you had a static route /24 that the IP falls in and a OSPF of /25 that it also falls in, the OSPF route will be chosen due to prefix.
The given answer and reason are correct.
CORRECTION ;) The static route DOES reach the host ... 172.16.0.1 - 254, BUT the keyword is "LEARNED" a STATIC route isn't "learned" so that leaves us with the closet network route that was learned dynamically....hence 172.16.0.128/25 (172.16.0.129 - 254 hosts) OSPF
why wouldn't it be B? even though metric is generally used for the value after the ad, they some times use the term metric to describe AD. this garbage is really confusing
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isn't the number 38443 pointing towards the ospf?
line D 172.16.0.192/29 doesnt it cover also the host
I don't understand why is not D the correct answer
172.16.0.128/25 has 128 addresses BUT usable hosts are only126 from to 0.129 to 0.255 which means 172.16.0.202 will be in this /25 subnet range WHILE 172.16.0.192/29 has 8 addresses BUT only six are usable hosts which is from 0.193 to .0.199 means 172.16.0.202 is out of /29 subnet range.
because for D to be correct, it should be a different mask in routing table 172.168.0.200/29 hosts: 172.168.0.201-172.168.0.206