Refer to the exhibit. The administrator configured route advertisement to a remote low resources router to use only the default route to reach any network but failed.
Which action resolves this issue?
Refer to the exhibit. The administrator configured route advertisement to a remote low resources router to use only the default route to reach any network but failed.
Which action resolves this issue?
Removing the line with the sequence number 10 from the prefix list resolves the issue. The prefix list currently has two entries: the first one denies any route with a subnet mask between 1 to 32 bits (which matches all routes), and the second one permits the default route. By removing the line with sequence number 10, the configuration will only deny all specific routes (due to the first deny statement), effectively limiting the advertisement to default route only.
The given answer is correct
https://community.cisco.com/t5/routing/very-quick-question-on-prefix-list-0-0-0-0-0/td-p/1356083 ip prefix-list 0.0.0.0/0 just matches the default-route not all routes. So that prefix-list filters out all routes except the default-route.
Answer D is correct
D is correct
deny 0.0.0.0/0 le 32 in prefix list means "any" route permit 0.0.0.0/0 in prefix list means default route So remove seq 5 will means only permit a default route advertise to the remote-host via the tunnel. I don't get the meaning of the question because don't know if the config is the "remote-host". A picture can help better explain this question
Can Anyone explain what is this "remote low resources router" trying to do ? what does "to use only the default route to reach any network" really mean ?
It means to keep the routing table small by only advertising to it a single default route. It will use this route to send all traffic.
Basically deny/32 mean deny all route becuase ipv4 is 32 bit
All answers are wrong. The permit statement permits all routing updates because it has a /0 mask. If they wanted to permit only default routes, the syntax should be 0.0.0.0/32, meaning all 3 bits of the advertised route must match 0.0.0.0. Also they should add le 0 at the end.
Typo - "all 3 3bits" should say all 32 bits.
Please disregard comment, was mixed up. /0 is correct.
El rango asumido para ge y le si no se especifica nada es 32