Refer to the exhibit.
An engineer is installing a new pair of routers in a redundant configuration. When checking on the standby status of each router, the engineer notices that the routers are not functioning as expected.
Which action will resolve the configuration error?
The action that will resolve the configuration error is to configure matching virtual IP addresses. In the provided exhibit, the virtual IP address for R1 is 192.168.0.1, while for R2, it is 192.165.0.1. For HSRP (Hot Standby Router Protocol) to function correctly, both routers must have the same virtual IP address configured for the same HSRP group. This allows the routers to correctly handle failover and redundancy operations.
The most situable for this question is D (configure unique virtual address) as is one of requirements for a group to work, as seeing in the image. The others are wrong for the following reason. (so Wrong based in the question) A) Not mandatory the timers must match to work on HSRP. on HSRP negotiation the active router will override the standby timers. https://www.cisco.com/c/en/us/products/collateral/switches/catalyst-9000/nb-06-cat-9k-stack-wp-cte-en.pdf B) On the image key string match so is not this reason HSRP cant be seen each other C) Wrong, priority is for selecing the active router, the best practice is should be different thus (WRONG) D) Different virtual Gateway configured on the same group number indeed will make HSRP routers negotiation fail for that group thus (CORRECT)
Correction of the link source https://community.cisco.com/t5/switching/hsrp-timers/td-p/1760156
There must be a typo in the possible answers as none of them are correct! D says to configure unique IP - they are already unique, but for HSRP to function, the virtual IP needs to match
Where do get this unique IP?
R2 is 192.165.0.1.
The answer to this question is not listed. The Virtual IPs must be identical on each standby Group. Unique should read identical.
The configuration is already got matching keys, the Virtual IP is not matching
it´s D, but the answer must be "configure a MATCHING virtual IP addresses", since they are already uniqe. B is wrong because both have Cisco123! as a key string, so they are matched.
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The R2 virtual IP doesn't match the R1's one
Answer :D As per the output result, R1 was configured as an Active Router due to the high priority number 255. Authentication will pass due to the same on both sides. Timer mismatch in both sites is not a problem in this case. Because the timer of the Active router is less than the Standby router’s. I mean the active Router will send a Hello packet every 5 seconds and it is met with the Standby router timer. The main mismatch is the virtual IP address. The virtual IP address must be the same in both Routers’ configuration.
D is correct, R1 VIP is 192.168.0.1 R2 VIP is 192.165.0.1 They have to match
Admin need to correct this as there is no correct answer. The Virtual IPs MUST MATCH. If you look at the exhibit, you will see that R1 and R2 have different VIPs.
D is correct
In the exhibit, the VIPs do not match; second octet are different (168 vs 165) Assuming that the two routers do have connectivity between them for the interfaces configured for hsrp, they both would have IPs in either 192.168.0.0/24 or 192.165.0.0/24 Latter not likely since 192.165.0.0 is not one of the reserved private IPs. But hsrp configuration won't let you configure a VIP that doesn't match the interface subnet. So it is really unlikely D is the situation on the actual exam even if the exam had it as MATCHING since on the exam, they would already be matching.
D is correct - key string is equal
Most likely there are two versions of this question in the actual exam, one with non-matching key-strings and one with non-matching virtual IP addresses. The question here is a mix of the two, it shows the exhibit of one version and the answers of the other one. So no correct answer exists in this case.
Hold up.. I didn't read the exhibit properly. It shows 192.168.0.1 and 192.165.0.1 so in this case the answer is D, as the two virtual IP addresses must match.
Again, scratch that. "Unique" as "different", which is wrong. It should say "matching". No answer is correct.
The answer is D in this case. Please note there's different variations of the exhibit. In another version, there's a difference in the key-string (cisco123! and Cisco123!).
D the keys are the same in the exhibit
In some places this question has a reference photograph and I see that the Virual IP is the same on both sides
I also go with D, if they can ask this exact question on the exam, they should give it as correct or they must say choose 2