Refer to the exhibit. What is the prefix length for the route that router1 will use to reach host A?
Refer to the exhibit. What is the prefix length for the route that router1 will use to reach host A?
The prefix length for the route that router1 will use to reach host A is /29. This is because, in the routing table, the specific route to reach 10.10.13.214 (Host A) is 10.10.13.208/29. This means that the router will use this route when forwarding packets to Host A.
Answer D /29 is correct. Why /29 cause lets see why 32 bit mask -29 bit mask=3 bits 2 to the power of 3 is 8 per subnet while 6 host in a subnet(2 power of 3 minus 2) So 8 bits in a subnet. Take this questions example. 1st Subnet = 10.10.13.0 - 10.10.13.7 2nd Subnet = 10.10.13.8 - 10.10.13.15 3rd Subnet = 10.10.13.16 - 10.10.13.23 .... ... Some numbered Subnet later =10.10.13.208 - 10.10.13.216 so 10.10.13.214 is in the range so that's the answer right there Reminder Each subnet has a Network and Broadcast Bit so for knowing how many host in a subnet need to ALWAYS MINUS 2. That's why we minus 2(remember just now with 2 power of 3 minus 2 so yup).
IT's D
it's /28 on the routing table not /29
D makes sense. 10.10.13.208/29 via 10.1.0.10.1
/28 is the network between R1 and S1 (Multilayer switch). The host is on another network.
I think C is the correct one. The route is 10.10.10.1 (to reach 10.10.13.214) which is the IP address of G0/0. The latter forms part of the 10.10.10.0/28 network. so should not be /28??
100% correct. Answer is C. /28
You guys have lost your minds go back to subnetting and routing please..
You are very very wrong. The network prefix in ip address is the network portion of the address. /29 looks like this 11111111.11111111.11111111.11111000 the 1s are the network prefix, while the 0s are the host portion. In this question the route 10.10.13.208/29 have the longest prefix ( the most 1s and the less 0s) therefor the router picks that route. and the address 10.10.13.214 falls into /29 subnet 10.10.13.208(Network ID) 209-214 usable hosts 10.10.13.215(Broadcast IP). Now the Network 10.10.10.0/28 is only between R1 and R2 or S1 i can't see the exhibit while I am answering that network is only between those 2 devices and their interfaces. Correct me if I am wrong does not fly here because i know I am right....
The correct Answer is C The route selected by R1 is 10.10.13.208/29 but the prefix for that route is the 10.10.10.0/28 network prefix . Therefore, /28 . Please correct me if im wrong
you are worng. if i am wgron correct me
This question is more about reading comprehension than technical knowledge. It is NOT asking "What is the prefix length for the network of host A?" It is asking "What is the prefix length for *THE ROUTE THAT* router1 *WILL USE TO REACH* host A?" The route used to reach host A is 10.10.10.1 That IP is part of the 10.10.10.0/28 subnet, which is clearly labelled as a /28. Therefore the answer is C.
No man. You made a similar response to another question a while back. 10.10.10.1 is *not* a route; it's just the IP address of the next hop. The route in this context refers to an entry in the routing table. 10.10.10.0/28 is just the prefix of the subnet directly connected to G0/0, which was created when you enter the command "ip address 10.10.10.2 255.255.255.240" on that interface. Host A is 10.10.13.214, and the most specific route in the routing table for that address is 10.10.13.208/29. That route *does* use 10.10.10.1 as its next hop, and that next hop *is* on the 10.10.10.0/28 subnet, but neither of those things is the *route*.
D is correct
Why is /29 ?
read my comment above.
It´s C for me
D: /29 is correct Basically look at the routing table and find the longest prefix route that's connected to Router1 and that is 10.10.13.208/29 via 10.10.10.1.